Question

Найти модуль комплексного числа : z=4-6i

Answer 1

$r= \sqrt{a^2+b^2}= \sqrt{16+36}= \sqrt{52} =2 \sqrt{13}$

Answer 2

$z=4-6i \\ |z| = \sqrt{a^2+b^2} \\ a= 4 \\ b= -6 \\ |z|= \sqrt{16+36} = \sqrt{52} = 2 \sqrt{13}$