Question

Решите уравнение, подробно:

Answer 1

$log_{5}(4-x)=3 \\ log_{5}(4-x)=3*log_{5}5 \\ log_{5}(4-x)=log_{5}125 \\ 4-x=125 \\ -x=125-4 \\ -x=121 \\ x=-121$

Answer 2

$log_5(4-x)=3\; \; ,\; \; ODZ:\; 4-x\ \textgreater \ 0\; ,\; \; x\ \textless \ 4\\\\Po\; opredeleniyu:\; \; \; 4-x=5^3\\\\4-x=125\\\\x=-121\ \textless \ 4\\\\Otvet:\; x=-121$