Question

(49^x)-(6*7^x)-7=0
(49^x)-(6*7^x)-7=0

Answer 1

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Answer 2

$1)49^{x}-6*7^{x}-7=0 \\ 7^{2x}-6*7^{x}-7 =0\\ 7^{x}=y; \\ y^{2}-6y-7=0 \\ D=36+28=64;y_{1}=(6+8):2=7;y_{2}=(6-8):2=-1 \\ 7^{x}=7; 7^{x} \neq -1 \\ 7^{x}=7^{1} \\ x=1$

Ответ: 1