Question

(1/3)^x+3=27^х
Решите уравнение

Answer 1

$( \frac{1}{3} )^{x+3}=27^{x} \\ 3^{-x-3}=3^{3x} \\ -x-3=3x \\ -x-3x=3 \\ -4x=3 \\ x=- \frac{3}{4}$

Answer 2

$( \frac{1}{3} ) ^{x+3} =27 ^{x} \\ \\( \frac{1}{3} ) ^{x+3} =3 ^{3x} \\ \\ ( \frac{1}{3} ) ^{x+3} =( \frac{1}{3} ) ^{-3x} \\x+3=-3x\\x+3x=-3\\4x=-3\\x=- \frac{3}{4}\\ \\x=- \frac{75}{100}\\ \\x=-0.75$