Question

Помогите решить пожалуйста!!!!!Только первый столбец.ЗАРАНЕЕ ОГРОМНОЕ СПАСИБО!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 1

$(2 \sqrt{5}+3 \sqrt{2})(\sqrt{5}-\sqrt{8})=2*5-2 \sqrt{40}+3 \sqrt{10}-3 \sqrt{8}=$
$10-4 \sqrt{10}+3 \sqrt{10}-3*2 \sqrt{2}=10- \sqrt{10} -6 \sqrt{2}$

$(\sqrt{42})^2-(2 \sqrt{6}-3 \sqrt{2} )^2=42-(4*6-6 \sqrt{12}+18 )=$
$=42-24-18+6*2 \sqrt{3} =6*2 \sqrt{3}$

$( \sqrt{11}- 0,5\sqrt{22} )(\sqrt{11}+ 0,5\sqrt{22})=( \sqrt{11})^2-(0,5\sqrt{22})^2=$
$=11-0,25*22=11(1-0,25*2)=11*0,5=5,5$