Question

найдите x, log6x=3 log62+ 0.5 log6 25-2 log6 3

Answer 1

$log_{6} x = 3 log_{6} 2 + 0,5log_{6} 25 - 2 log_{6} 3 \\ log_{6} x = log_{6} 2^{3} + log_{6} 25^{0,5} - log_{6} 3^{2} \\ log_{6} x = log_{6} 8 + log_{6} 5 - log_{6}9 \\ log_{6} x = log_{6} \frac{8*5}{9} \\ x = \frac{40}{9} \\ x = 4 \frac{4}{9}$