Question

найти значение выражения (1- log2 12)(1- log6 12)

Answer 1

$(1- log_{2}12 )(1-log_{6} 12)=(log_{2} 2- log_{2}12 )(log_{6} 6-log_{6} 12)=$$log_{2} \frac{2}{12} *log_{6} \frac{6}{12} =log_{2} \frac{1}{6} *log_{6} \frac{1}{2} =- log_{2} 6* log_{6} \frac{1}{2} =-log_{2} \frac{1}{2} = log_{2} 2=1$