Question

Сократить дробь $x^2+3x-4/x-4$

Answer 1

$\frac{ x^{2} +3x-4}{x+4} = \frac{(x-1)(x+4)}{x+4} =x-1\\ x^{2} +3x-4=0\\D=9+16=25 \\ \sqrt{D}=5 \\ x_{1} = \frac{-3+5}{2} = \frac{2}{2} =1\\ x_{2} = \frac{-3-5}{2} = \frac{-8}{2} =-4\\ x^{2} +3x-4=(x-1)(x+4)$