Question

решить неравенство$( \frac{1}{2} ) x^{2} -5\ \textgreater \ ( \frac{1}{16} )$x

Answer 1

$\frac{1}{2}x^2-5\ \textgreater \ \frac{1}{16}x\, |\cdot 16\\\\8x^2-x-80\ \textgreater \ 0\\\\D=1+4\cdot 8\cdot 80=2561=13\cdot 197\\\\x_1=\frac{1-\sqrt{2561}}{16},\; \; x_2=\frac{1+\sqrt{2561}}{16}\\\\+++(x_1)---(x_2)+++\\\\x\in (-\infty,\frac{1-\sqrt{2561}}{16})U(\frac{1+\sqrt{2561}}{16},+\infty)$