Question

Решите интеграл:
(2x^3+1)^4*x^2*dx

Answer 1

$\int {(2 x^{3}+1) ^{4} x^{2} } \, dx = \frac{1}{8} \int {(2 x^{3}+1) ^{4} d(2x^{3}+1) =$
$= \frac{(2x^{3}+1) ^{5} }{8\cdot 5}+C= \frac{(2x^{3}+1) ^{5} }{40}+C$