Question

вычислите :9^(3/2) + 〖27〗^(2/3) - (1/16)^(-3/4)

Answer 1

$9^{\frac{3}{2}}+27^{\frac{2}{3}}-(\frac{1}{16})^{-\frac{3}{4}}=(\sqrt9)^3+(\sqrt[3]{27})^2-(\sqrt[4]{16})^3=\\\\=3^3+3^2-2^3=27+9-8=28$