Question

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Answer 1

$lim_{x\to 0}\, (1-5x)^{\frac{2}{x}}=lim_{x\to 0}\, (1-5x)^{-\frac{1}{5x}\cdot \frac{2\cdot (-5x)}{x}}=\\\\=lim_{x\to 0}\, e^{\frac{-10x}{x}}=e^{-10}$