Question

lim x стремиться к -2, 3x+6/x^3+8

Answer 1

$\lim_{x \to {-2}} \frac{3x+6}{x^3+8}= \lim_{x \to {-2}} \frac{3(x+2)}{(x+2)(x^2-2x+4)}= \lim_{x \to {-2}} \frac{3}{(x^2-2x+4)}=$
$\lim_{x \to {-2}} \frac{3}{(4+4+4)}= \frac{3}{12}=0.25$