Question

log₂7 - log₂63 + log₂36

Answer 1

$log_{2}7-log_{2}63+log_{2}36=log_{2}( \frac{7}{63} *36)=log_{2}4=log_{2}2^{2}=2$

Answer 2

$log_{2}7-log_{2}63+log_{2}36=log_{2}36-(log_{2}63-log_{2}7)=log_{2}36-log_{2}\frac{63}{7}=log_{2}36-log_{2}9=log_{2}\frac{36}{9}=log_{2}4=2$