Предмет: Алгебра, автор: Аноним

1.m3-n3
2.c3+8
3.27a3-b3
4.125+a3b3
5.x6-y9
6.1000a12b3+0,001c9d15
Решите пожалуйста) Добра Вам)

Ответы

Автор ответа: Alphaeus
36
Насколько я понимаю, нужно разложить на множители. Все эти примеры решаются с помощь формул суммы или разности кубов:
a^3 - b^3 = (a - b)(a^2 + ab + b^2)\\ a^3 + b^3 = (a + b)(a^2 - ab + b^2)

1)m^3-n^3=(m-n)(m^2+mn+n^2)\\ 2)c3+8=(c+2)(c^2-2c+4)\\ 3)27a3-b3=(3a-b)(9a^2+3ab+b^2)\\ 4)125+a3b3=(5+ab)(25-5ab+a^2b^2)
5)x^6-y^9=(x^2-y^3)(x^4+x^2y^3+y^6)\\ 6)1000a^{12}b^3+0,001c^9d^{15}=\\ =(10a^4b+0,1c^3d^5)(100a^8b^2-a^4bc^3d^5+0,01c^6d^{10})
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