Question

Дробное линейное уравнение. Срочно!

Answer 1

$\frac{7}{8} - \frac{1}{8} ( \frac{x-5}{4} - \frac{14-2x}{5} )= \frac{x-9}{2} - \frac{x-1}{4}$

$\frac{7}{8}- \frac{1}{8}* \frac{5x-25-56+8x}{20} = \frac{x-9}{2} - \frac{x-1}{4} \\ \\ \frac{7}{8}- \frac{1}{8}* \frac{13x-81}{20}= \frac{x-9}{2} - \frac{x-1}{4} \\ \\ \frac{7}{8} - \frac{13x-81}{160} = \frac{x-9}{2} - \frac{x-1}{4} \\ \\ \frac{7*20-13x+81}{160} = \frac{2x-18-x+1}{4} \\ \\ \frac{140-13x+81}{160} = \frac{x-17}{4} \\ \\ \frac{221-13x}{160} = \frac{x-17}{4}~|*4 \\ \\ \frac{221-13x}{40} =x-17$

$40(x-17)=221-13x \\ 40x-680=221-13x \\ 53x=901 \\ x=17$

Ответ: $17$

Answer 2

$\frac{7}{8} - \frac{1}{8} \cdot (\frac{5x-25-56+8x}{20})=\frac{2x-18-x+1}{4}; \ \ \frac{7}{8} - \frac{13x-81}{160}=\frac{x-17}{4}; \\ \\ \frac{140-13x+81}{160}-\frac{x-17}{4}=0; \ \ \ \frac{-13x+221-40x+680}{160}=0; \ \ \frac{-53x+901}{160}=0; \\ \\ -53x+901=0; \ \ -53x=-901; \ \ x=\frac{-901}{-53}=17$