Question

( корень из )3 sin x − tgx = 0;
sinx + 2cosx = 0;

Answer 1

1)√3sinx-sinx/cosx=0
cosx≠0⇒x≠π/2+πn
√3sinxcosx-sinx=0
sinx(√3cosx-1)=0
sinx=0⇒x=πn
cosx=1/√3⇒x=+-arccos1/√3+2πn
2)sinx+2cosx=0/cosx≠0
tgx+2=0
tgx=-2
x=-arctg2+πn