Предмет: Химия, автор: Lina145

Сколько граммов ацетилена потребуется для получения 1 кг. Винилхлорида (CH2=CHCl) ?

Ответы

Автор ответа: gusmakvlad
2
C2H2+HCl=  Ch2=CHCl
1 моль          1 моль
Mr(C2H3Cl)=62.5
n(C2H2)=n(CH2=CHCl)=1000/62.5=16 моль
Mr(C2H2)=26
m(C2H2)=26*16=416 г
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