Question

Решите,пожалуйста!
(3c-5)^2+10c+9
(3n-2)(3n+2)-(2n-3)^2=3n(n+7)-17

Answer 1

$9c^2+25-30c+10c+9=9c^2-20c+34$

$9n^2-4-4n^2-9+12n=3n^2+21n-17$
$2n^2-9n+4=0$
D=81-32=49
x1=4
x2=1/2