Question

Помогите, пожалуйста, решить)

Answer 1

(1/2)^log₆ 2  *  3^log₆ (1/2) =
=(2⁻¹)^log₆ 2 * 3^(log₆ 1 - log₆ 2)=
=(2⁻¹)^log₆ 2 * 3^(0 - log₆ 2)=
=(2⁻¹)^log₆ 2 * (3⁻¹)^log₆ 2=
=(2⁻¹ * 3⁻¹)^log₆ 2 =
=(6⁻¹)^log₆ 2=
=      1     =   
    6^log₆ 2    
=1/2