Question

Sin3α/Sinα- cos3α/cosα

Answer 1

sin3a/sina-cos3a/cosa=(sin3acosa-cos3asina)/sinacosa=sin(3a-a):1/2sin2a=
=sin2a:1/2sina=2

Answer 2

$\frac{sin3 \alpha }{sin \alpha } - \frac{cos3 \alpha }{cos \alpha } = \frac{sin3 \alpha cos \alpha -cos3 \alpha sin \alpha }{sin \alpha cos \alpha } = \frac{sin(3 \alpha - \alpha )}{0.5sin2 \alpha }= \frac{sin2 \alpha }{0.5sin2 \alpha }=2$