Question

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Answer 1

$\displaystyle \tt \bigg(3\frac4{25} +0,\! 24\bigg)\cdot 2,\! 15+\bigg(5,\! 1625-2\frac3{16} \bigg) \cdot \frac25 =\\ \\ =\bigg(3\frac{4}{25} +\frac{24}{100} \bigg) \cdot 2\frac{15}{100} +\bigg(5\frac{1625}{10\,000}-2\frac{3}{16} \bigg) \cdot \frac25 =$

$\displaystyle \tt =\bigg(3\frac{4}{25} +\frac{6}{25} \bigg) \cdot 2\frac{3}{20} +\bigg(5\frac{325}{2000}-2\frac{3}{16} \bigg) \cdot \frac25 =\\ \\ =3\frac{10}{25} \cdot \frac{2\cdot 20 +3}{20} +\bigg(5\frac{65}{400}-2\frac{3}{16} ^{(5}\, \bigg) \cdot \frac25 =$

$\displaystyle \tt =\frac{3\cdot 5+2}{5} \cdot \frac{40+3}{20} +\bigg(4\frac{80+13}{80}-2\frac{15}{80} \bigg) \cdot \frac25 =\\ \\ =\frac{17}{5} \cdot \frac{43}{20} +2\, \frac{93-15}{80} \cdot \frac25 =\frac{17\cdot 40+17\cdot 3}{100} +2\, \frac{78}{80} \cdot \frac25 =$

$\displaystyle \tt =\frac{680+51}{100} +2\, \frac{39}{20} \cdot \frac15 =\frac{731}{100} +\frac{2\cdot 40+39}{40} \cdot \frac25 =\\ \\ =7\frac{31}{100} +\frac{119\cdot 2}{40\cdot 5} =7\frac{31}{100} +\frac{119}{100} =7\frac{150}{100} =8\frac5{10} =8,\! 5$

Ответ: 8,5.