Question

Найти производную f(x)=(5x в квадрате-1)*(x+4)

Answer 1

$f'(x)=(5 x^{2} -1)'*(x+4)+(5 x^{2} -1)*(x+4)'=$
$10x(x+4)+(5 x^{2} -1)*1=10 x^{2} +40x+5 x^{2} -1=15 x^{2} +40x-1$