Question

Решите уравнение:
2sin(π/3-3x)=1

Answer 1

sin(3x-π/3)=-1/2
3x-π/3=-π/6+2πn U 3x-π/3=7π/6+2πk
3x=π/6+2πn U 3x=3π/2+2πk
x=π/18+2πn/3,n∈z U x=π/2+2πk/3,k∈z