Question

Помогите, пожалуйста, написать программу в VBA. Последовательность действительных чисел оканчивается нулем. Найти количество членов этой
последовательности.

Answer 1

Dim r As Single, s As String, d, v As String, A() As Single
Dim t As String, z As Integer, k As Integer, h As Integer, g As Integer
h = Rnd * 100
ReDim A(h) As Single
For i = 1 To h
A(i) = Rnd * 1000
s = CStr(A(i))'
MsgBox s
d = Split(A(i), ",")'
MsgBox d(0)
v = d(0)
z = Len(v)
s = Mid(v, z, 1)
If s = "0" Then t = t & CStr(A(i)) + " ": g= g+1
Next
MsgBox g
MsgBox t

Answer 2

Sub aaa()
    Const n = 50
    Dim a(1 To n) As Double, Zero As Boolean
    Randomize Timer
    For i = 1 To n
        a(i) = Int(21 * Rnd - 10)
    Next i
    k = 0: Zero = False
    For i = 1 To n
        If a(i) = 0 Then
            Zero = True
            Exit For
        End If
    Next i
    If Zero Then
        MsgBox "Количество членов последовательности равно " + CStr(i)
    Else
        MsgBox "В последовательности нет нулей"
    End If
End Sub