Question

$\left \{ {{x-y=-2} \atop {3^x*2^y = \frac{1}{9} }} \right.$

Answer 1

$y=x+2\\ 3^x*2^{x+2}= \frac{1}{9} \\3^x*2^x*2^2= \frac{1}{9} \\(3*2)^x*4= \frac{1}{9} \\6^x= \frac{1}{9}:4\\6^x= \frac{1}{9} * \frac{1}{4}\\6^x= \frac{1}{36} \\6^x=6^{-2}\\x=-2\\y=-2+2=0\\(-2;0)$