Предмет: Алгебра, автор: lolkot

найдите площадь фигуры ограниченной линиями y=1-x^2, y=0

Ответы

Автор ответа: Аноним

Найдём границы интегрирования
1 - х² = 0
х² = 1
х = +- 1
Теперь ищем интеграл в пределах от -1 до 1 Под интегралом стоит: (1 - х²)dx
Он = (х - х³/3) в пределах от -1 до 1
=(1 - 1/3)-( - 1 + 1/3) = 1 - 1/3 +1 - 1/3= 2 - 2/3= 4/3

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