Question

Решить систему
X в квадрате -2y=54
y=x-3

Answer 1

$\left \{ {{ x^{2} -2y=54} \atop {y=x-3}} \right. \\ \left \{ {{ x^{2} -2(x-3)=54} \atop {y=x-3}} \right. \\ \left \{ {{ x^{2} -2x+6-54=0} \atop {y=x-3 \\ } \right. \\ \left \{ {{ x^{2} -2x-48=0} \atop {x=2}} \right.$
$x^{2} -2x-48=0$
x= - 6 ;x= 8   по т. Виета
$\left \{ {{x=-6; x=8} \atop {y=-6-3; y=8-3}} \right. \\ \left \{ {{x=-6;x=8} \atop {y=-8; y=5}} \right.$
A(-6;-8); B(8;5)