Question

помогите решить пжлст

Answer 1

1
1)a-1+2/(a+1)=(a²-1+2)/(a+1)=(a²+1)/(a+1)
2)(a²+1)/(a+1) : (a²+1)/(a+1)²=(a²+1)/(a+1)*(a+1)²/(a²+1)=a+1
2
$(3 \sqrt{2} -7 \sqrt{2} )^2+49*3=(-4 \sqrt{2} )^2+147=32+147=179$

Answer 2

$\frac{ a^{2}-1+2 }{a+1}* \frac{(a+1)^2}{a^2+1} = \frac{a^2+1}{a+1} * \frac{(a+1)^2}{a^2+1} =a+1$

№2 
=18+98-2$\sqrt{18*98} +49*3=116-84+147=179$