Question

3sin(π/2+t)-sin(3π/2+t)-8cos(2π-t)

Answer 1

3sin($\frac{ \pi }{2}$ + t) - sin($\frac{3 \pi }{2}$ + t) - 8cos($2 \pi$ - t) = 3cost + cost - 8cost = 4cost - 8cost = -4cost