Question

(x+10)^2=40x решите плиз

Answer 1

$x^{2} +20x+100-40x=0, \\ x^{2} -20x+100=0, \\ D=400-400=0, \\ x_{1}= x_{2}= \frac{20}{2}=10.$

Answer 2

\\\\\\\\\\\\\\\\\\\\\\\\\\