Question

$\sqrt{x-5}=4; \sqrt{-32-9x}=2; \sqrt{4x+32}/7=6; \sqrt[3]{x+10} =2; \sqrt \frac{4x+32}{7} =6$

Answer 1

$\sqrt{x-5} =4$
$x-5=16$
x=21

№2
$\sqrt{-32-9x} =2$
$-32-9x=4$
- 9x=36
x= - 4

№ 3
$\frac{ \sqrt{4x+32} }{7} =6$
$\sqrt{4x+32} =42$
4x+32=1764
4x=1732
x=433

№4
$\sqrt[3]{x+10} =2$
$x+10=8$
x= - 2
№5
$\frac{4x+32}{7} =36$
4x+32=252
4x=220
x=55