Question

уравнение: (х-4)(х^4-17х^2+16)=0

Answer 1

$(x-4)(x^4-17x^2+16)=0 \\ \\ x-4=0 \\ x=4 \\ \\ x^4-17x^2+16=0 \\ x^2=a \\ a^2-17a+16=0 \\ (a-1)(a-16)=0 \\ a=1,a=16 \\ x^2=1 , x=б1 \\ x^2=16, x=б4$

Ответ: $1;б4$