Question

((5/(x-2))-x-2)*((2-x)/(x^2-6x+9))

Answer 1

$(\frac{5}{x-2}-(x+2))*(\frac{2-x}{x^2-6x+9})=\frac{5-(x+2)(x-2)}{x-2}*\frac{-(x-2)}{(x-3)^2}=\\=\frac{5-(x^2-4)}{1}*\frac{-1}{(x-3)^2}=\frac{x^2-9}{(x-3)^2}=\frac{(x-3)(x+3)}{(x-3)^2}=\frac{x+3}{x-3}$