Question

Помогите пожалуйста
1. \frac{(3 \sqrt{2})^{2} }{4}
2. 2√19·2√3·√57

Answer 1

1.  $\frac{(3 \sqrt{2})^{2} }{4}= \frac{ 3^{2}*{( \sqrt{2)}^2} }{4} = \frac{9*2}{4} = \frac{9}{2} =4.5$
2.  2√19·2√3·√57=2*2*√(19*3*57)=4√(57*57)=4*√57²=4*57=228

Answer 2

$\\\frac{(3\sqrt{2})^2}{4} = \frac{3^2(\sqrt{2})^2}{4} = \frac{9*2}{4} = \frac{9}{2} = 4.5\\ \\2\sqrt{19}*2\sqrt{3}*\sqrt{57} = 4\sqrt{19*3}*\sqrt{57} = 4*\sqrt{57}*\sqrt{57} = 4*57 = 228$