Question

Задания во вкладках.........

Answer 1

$\log_{2}32 \sqrt[3]{x^2}, \ \log_{2}x = b\\ x = 2^b\\ \log_{2}32 \sqrt[3]{x^2} = \log_{2}2^5 \sqrt[3]{2^{2b}} = \\ = \log_{2}2^{5+ \frac{2b}{3}} = 5+ \frac{2b}{3}$ $\\f(x) = \sin5x \cos6x - \cos5x \sin6x = -\sin x\\ f'(x) = (-\sin x)' = -\cos x$

Answer 2

$log_2(32 \sqrt[3]{ x^{2} })=log_2{32}+log_2 \sqrt[3]{ x^{2} }=5+ \frac{2}{3}b$

sin5xcos6x-co5xsin6x=sin(5x-6x)=sin(-x)=-sinx
(-sinx)`=-(sinx)`=-cosx