Question

помогите, очень надо )

Answer 1

1) f ' =$x^{3}-6x=-27+18= -9$
2) f ' =$\frac{2x(2x+1)-2( x^{2} -1)}{(2x+1)^2} = \frac{4 x^{2} +2x-2 x^{2} +1}{(2x+1)^2}= \frac{2 x^{2} +2x+1}{(2x+1)^2} = \frac{5}{9}$
3) f ' =$4x(4+ x^{3})+3 x^{2} (2 x^{2} +1)=4x+4 x^{4} +6 x^{4}+3 x^{2} =10 x^{4}+3 x^{2} +4x$ =17

4)
f ' =2sinx+2x*cosx-0=2*$\frac{ \sqrt{2} }{2} +2* \frac{ \pi }{4} * \frac{ \sqrt{2} }{2} = \sqrt{2} + \sqrt{2$*$\frac{ \pi }{4}$