Question

Пожалуйста, ребяяят !
Упростить :
sinL/1+cosL + 1+cosL/sinL

Answer 1

$\frac{sin \alpha }{1+cos \alpha }+\frac{1+cos \alpha }{sin \alpha }=\frac{sin^2 \alpha +(1+cos \alpha )^2}{sin \alpha (1+cos \alpha )}=\frac{sin^2a +1+2cos \alpha +cos^2 \alpha }{sin \alpha (1+cos \alpha )}=\\\\=\frac{1+1+2cos \alpha }{sin \alpha (1+cos \alpha )}=\frac{2(1+cos \alpha )}{sin \alpha (1+cos \alpha )}=\frac{2}{sin \alpha }$