Question

решите систему уравнений { 4(х-2)-3(y+3)=1
{3(х+2)-2(х-y)=5

Answer 1

4х-8-3у+9=1
4х-3у=1+8+9
4х-3у=18
3х+6-2х+2у=5
х+2у=5-6
х+2у=-1
х=-1-2у
4*(-1-2у)-3у=18
-4-8у-3у=18
-11у=18+4
-11у=22
у=-2
х=-1-2*(-2)
х=-1+4
х=3