Question

Решить неравенство $x^{2} -36 \leq 0$

Answer 1

$x^{2} -36 \leq 0 \\ \\ (x-6)(x+6) \leq 0 \\ \\ (x-6)(x+6)=0 \\ x=-6; \\ x=6 \\ \\ -6 \leq x \leq 6$