Question

-19/(x+5)^2-6>0 помогииитеее

Answer 1

$\frac{ -19}{(x+5)^2-6}\ \textgreater \ 0$
$(x+5)^2-6\ \textless \ 0$
$x^{2} +10x+25-6\ \textless \ 0$
$x^{2} +10x+19\ \textless \ 0$
D=100-76=24
x1= - 5+√6
x2= - 5 -√6
Ответ ( - 5-√6; - 5 +√6)