Question

Найти значение производной:
F(x)=4x-7\x^2+4 ;при x0=0

Answer 1

$f(x)=\frac{4x-7}{x^2+4}\\\\f'(x)=\frac{4(x^2+4)-(4x-7)\cdot 2x}{(x^2+4)^2}=\frac{4x^2+16-8x^2+14x}{(x^2+4)^2}=\frac{-4x^2+14x-16}{(x^2+4)^2}\\\\f'(0)=\frac{16}{4^2}=1$