Question

упростите
$2 \frac{2}{3}$x²y⁸($-1 \frac{1}{2}$xy³)⁴

Answer 1

$2 \frac{2}{3} x^{2}y ^{3}*(-1 \frac{1}{2}xy ^{3}) ^{4}=2 \frac{2}{3} x^{2}y ^{3}*(- \frac{3}{2}xy ^{3}) ^{4}= \frac{8}{3} x^{2}y ^{3}* \frac{81}{16} x^{4}y ^{12}= \frac{27}{2} x^{2+4}$$y^{3+12}= \frac{27}{2} x^{6}y ^{15}=13 \frac{1}{2} x^{6}y ^{15}$