Question

Прошу, сократите дробь ( 7^n+1* 2^3n-4 ): 56^n-1

Answer 1

$\bold{\dfrac{7^{n+1}\cdot 2^{3n-4}}{56^{n-1}}=}\dfrac{7^{n+1}\cdot 2^{3n-4}}{(7\cdot 2^3)^{n-1}}=\\\\\\=\dfrac{7^{n+1}\cdot 2^{3n-4}}{7^{n-1}\cdot 2^{3n-3}}=7^{n+1-(n-1)}\cdot 2^{3n-4-(3n-3)}=\\\\\\=7^2\cdot 2^{-1}=\dfrac {49}2\bold{=24,5}$