Question

sin2x-√3cos2x=0
ответ?

Answer 1

sin2x-√3cos2x=0 |:cos2x≠0, 2x≠π/2+πn, n∈Z, x≠π/4+πn/2, n∈Z
tg2x-√3=0             
tg2x=√3
2x=π/3+πn, n∈Z
x=π/6+πn/2, n∈Z