Предмет: Геометрия, автор: sasha251998

Диагонали трапеции АВСD с основаниями АВ иСD пересекаются в точке О.Найти АВ если ОВ=4sm ОD=10sm DC=25sm

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Автор ответа: icesword

0

произвидение диагоналей равно удвоенному произведению боковых сторон(проверь на всякий случай на викип) 4+4=8 10=10=20

8*20=160 160:25=

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