Question

(х-3)(х+4)-2(3х-2)=(х-4)в квадрате

Answer 1

( x-3)(x+4) - 2(3x-2) = $(x-4)^2$
$x^2+x -12-6x+4=x^2 -8x+16 ; \\ x^2-x^2 +x+8x-6x=16+12; \\ 3x=28; \\ x= \frac{28}{3} ; \\ x=7 \frac{1}{3}$