Question

$\sqrt{-88-19x} = -x$

Answer 1

$\sqrt{-88-19x} = -x (\sqrt{-88-19x})^{2} = (-x)^{2} -88 - 19x = x^{2} x^{2} +19x+88= 0 D = b^{2} -4ac= 361 - 4 * 1 * 88 = 361 - 352 = 9 x_{1} = \frac{-b+ \sqrt{D} }{2a} = \frac{-19+3}{2} = \frac{-16}{2} = -8 x_{2} = \frac{-b- \sqrt{D} }{2a} = \frac{-19-3}{2} = \frac{-22}{2} = -11$

Ответ: -8; -11.