Question

помогите решить...........

Answer 1

$\frac{2a ^{2}-4a+2 }{3a ^{4} } * \frac{a}{2(a-1)} = \frac{2(a ^{2}-2a+1) }{3a ^{4} } * \frac{a}{2(a-1)} =\frac{2(a-1) ^{2} }{3a ^{4} } * \frac{a}{2(a-1)} = \frac{a-1}{3a ^{3} }$
отв: С

Answer 2

(2a²-4a+2)/3a^4 *a/2(a-1)=2(a-1)²/3a^4*a/2(a-1)=(a-1)/3a³