Предмет: Алгебра, автор: Lia2012ee

Решите плиз а4:( не могу понять как решается

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Автор ответа: julyap

$-6a ^{4} b ^{4} *N=12a ^{4} b ^{8} \\ \\ N= \frac{12a ^{4} b ^{8} }{-6a ^{4} b ^{4} } =-2a ^{4-4} b ^{8-4} =-2b ^{4} \\ \\ Otviet: 4)-2b ^{4}$

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